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Q.
If earth suddenly stop rotating, then the weight of an object of mass $m$ at equator will $[\omega$ is angular speed of earth and $R$ is its radius].
Gravitation
Solution:
At the equator,
Apparent weight, $w'=w-m \omega^{2} R$
if Earth stops rotating, $w'$ will be equal to $\omega$.
Thus, the weight of an object of mass $m$ at equator will increase by $m \omega^{2} R$,