Question

If each capacitor of $18 \mu F$ arranged as shown in figure below, then the equivalent capacitance between the points $P$ and $Q$

• A. $30\, \mu F$
• B. $90\, \mu F$
• C. $20\, \mu F$
• D. $18\, \mu F$

Answer 1

Answer: (A)

$C_{P}=C_{1}+C_{2}=18+18=36\, \mu F$

$\frac{1}{C_{s}}=\frac{1}{36}+\frac{1}{18}=\frac{1+2}{36}$
$C_{s}=12\, \mu F$
$C_{P}=12+18=30\, \mu F$