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  4. If E is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

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Q. If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

Electric Charges and Fields

Solution:

Electrostatic energy density
$\frac{\text { Energy }}{\text { Volume }}=\frac{\varepsilon_{0} E ^{2}}{2}$
$\propto E ^{2}$