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Q. If E = energy, G = gravitational constant, I = impulse and M = mass, then dimesions of $ \frac{ GLM^2 }{ E^2 } $ are same as that of

Bihar CECEBihar CECE 2006Physical World, Units and Measurements

Solution:

Dimensions of $ \frac{ GIM^2 }{ E^2 } $
= $ \frac{ [ M^{ - 1} L^3 T^{ - 2} ] [ MLT^{ - 1} ] [ M^2 ] }{ [ ML^2 T^{ - 2} ]^2 } $
= [T] = dimensions of time