1. Tardigrade
  2. Question
  3. Mathematics
  4. If displaystyle∑r=02 n ar(x-1)r= displaystyle∑r=02 n br(x-2)r and br=(-1)r-n for all r ≥ n, then an is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $\displaystyle\sum_{r=0}^{2 n} a_r(x-1)^r=\displaystyle\sum_{r=0}^{2 n} b_r(x-2)^r$ and $b_r=(-1)^{r-n}$ for all $r \geq n$, then $a_n$ is

Binomial Theorem

Solution:

Correct answer is (c) ${ }^{2 n+1} C_n$