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Q. If direction cosines of a vector of magnitude $3$ are $\frac {2}{3},-\frac {1}{3},\frac{2}{3}$ and $a > 0,$ then vector is

KCETKCET 2015Three Dimensional Geometry

Solution:

Unit vector with direction cosine $\frac{2}{3},-\frac{1}{3}, \frac{2}{3}$ is given by
$\hat{a}=\frac{2}{3} \hat{ i }-\frac{1}{3} \hat{ j }+\frac{2}{3} \hat{ k }$
Thus vector with magnitude 3 and direction cosine as above is given by
$3 \hat{a}=2 \hat{ i }-\hat{ j }+2 \hat{ k }$