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Q. If $\Delta H$ is the change in enthalpy and $\Delta E$, the change in internal energy accompanying a gaseous reaction, then

AIPMTAIPMT 1990Thermodynamics

Solution:

As $\Delta H = \Delta E + \Delta n_g RT$
if $n_p < n_r; \Delta n_g = n_p - n_r = - ve.$
Hence $\Delta H < \Delta E.$