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  4. If Cu2+ ions is treated with excess of KCN, the complex formed is

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Q. If $Cu^{2+}$ ions is treated with excess of $KCN$, the complex formed is

UP CPMTUP CPMT 2015The d-and f-Block Elements

Solution:

$Cu^{2+}$ is reduced to $Cu^{+}$ which forms complex $K_{3}[Cu(CN)_{4}]$
$2CuSO_{4}+10KCN \to 2K_{3}[Cu(CN)_{4}] + 2K_{2}SO_{4}+(CN)_{2}$