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Q. If $\cot x=\frac{-5}{12}$ and $x$ lies in second quadrant, then choose the correct option.

Trigonometric Functions

Solution:

Since, $\cot x=\frac{-5}{12}$, we have $\tan x=-\frac{12}{5}$
Now,
$\sec ^2 x =1+\tan ^2 x $
$ =1+\frac{144}{25}=\frac{169}{25}$
Hence, $ \sec x=\pm \frac{13}{5}$
Since, $x$ lies in second quadrant, $\sec x$ will be negative.
Therefore, $\sec x=-\frac{13}{5}$,
which also gives $\cos x=-\frac{5}{13}$
Further, we have
and $\sin x=\tan x \cos x =\left(-\frac{12}{5}\right) \times\left(-\frac{5}{13}\right)=\frac{12}{13} $
and $ \operatorname{cosec} x =\frac{1}{\sin x}=\frac{13}{12}$