Tardigrade
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Tardigrade
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Mathematics
If cos x = tan y, cot y = tan z and cot z = tan x, then sin x =
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Q. If cos x = tan y, cot y = tan z and cot z = tan x, then sin x =
A
$\frac{\sqrt{5}+1}{4}$
B
$\frac{\sqrt{5}-1}{2}$
C
$\frac{\sqrt{5}+1}{2}$
D
$\frac{\sqrt{5}-1}{4}$
Solution:
Correct answer is (d) $\frac{\sqrt{5}-1}{4}$