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Q.
If coefficient of $a^{2}b^{3}c^{4}$ in $(a+b+c)^{m}$ (where m $\in N$) is $L \left(L\ne0\right),$ then in same expansion coefficient of $a^{4}b^{4}c^{1}$ will be
Binomial Theorem
Solution:
$As L\ne0$
$ \therefore m=2+3+4=9 $
$\therefore L=\frac{9!}{2!3!4!} $
Now coefficient of $a^{4} b^{4} c =\frac{9!}{4!4!1!}=\frac{L}{2}$