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Q. If change in angular momentum when an electron makes a transition corresponding to the third line of the Balmer series in $Li ^{2+}$ ion is $X \times \frac{h}{2 \pi}$, then value of $X$ will be

Structure of Atom

Solution:

image
Third line of Balmer series is $5 \rightarrow 2$
Therefore, change in angular momentum is
$=\frac{5 h}{2 \pi}-\frac{2 h}{2 \pi}=\frac{3 h}{2 \pi}$