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Q. If $ C{{l}_{2}} $ is passed into hot $ NaOH $ solution, oxidation number of chlorine changes from (1) 0 to + 5 (2) 0 to -1 (3) 0 to +1 (4) 0 to +7

BHUBHU 2008

Solution:

On passing chlorine gas into hot and concentrated $ NaOH $ solution, sodium chlorate and sodium chloride are obtained.
$ \therefore $ Oxidation number of chlorine changes from 0 to + 5 and 0 to -1.

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