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Q. If $\beta$ satisfies the inequation $x^2 - x - 6 > 0$, then a value exists for

COMEDKCOMEDK 2014Complex Numbers and Quadratic Equations

Solution:

Since, : $\beta$ satisfy the inequation $x^2 - x - 6 > 0$
$\Rightarrow \,\beta^2 - \beta - 6 > 0$
$\Rightarrow \: (\beta - 3)(\beta + 2) > 0 $
$\Rightarrow \: \beta > 3, \beta < -2$