If b is the first term and r is the common ratio of an infinite G.P. then sum is 5
$5=\frac{b}{1-r}$]
$1-r=\frac{b}{5}$
$r=1-\frac{b}{5}$
$r=\frac{5-b}{5}$
∴ -1 < r < 1
$\therefore -1<\frac{5-b}{5}<1$
- 5 < 5 - b < 5
- 5 < 5 - b < 5
- 10 < - b < 0
0 < b < 10
b $\in$ (0,10)