Question

If Avogadro number is $6 \times 10^{23}$, then number of protons, neutrons and electrons is $14\, g$ of ${ }_{6} C ^{14}$ are respectively

• A. $36 \times 10^{23}, 48 \times 10^{23}, 36 \times 10^{23}$
• B. $36 \times 10^{23}, 36 \times 10^{23}, 36 \times 10^{23}$
• C. $48 \times 10^{23}, 36 \times 10^{23}, 48 \times 10^{23}$
• D. $48 \times 10^{23}, 48 \times 10^{23}, 36 \times 10^{23}$

Answer 1

Answer: (A)

Each atom of ${ }_{6} C^{14}$ contains $6p,\, 6 e$ and $8\, n$.
$\therefore \ln 14\, g$ of $_{6} C^{14}$
$p=6 \times 6 \times 10^{23}=36 \times 10^{23}$
$n=8 \times 6 \times 10^{23}=48 \times 10^{23}$
$e=p=36 \times 10^{23}$