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Q. If atomic radius of barium is $2.176\, \mathring{A}$ and it crystallises in b.c.c. unit cell, the edge length of unit cell is

The Solid State

Solution:

Cube diagonal,
$ 4r = \sqrt{3}a$
$a = \frac{4}{\sqrt{3}} r$
$ = \frac{4\times 2.176}{\sqrt{3}}\mathring{A}$
$ = 5.025 \,\mathring{A}$