Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $\arg (z)<0$, then $\arg (-z)-\arg (z)=$

Complex Numbers and Quadratic Equations

Solution:

$-\theta=\arg (z) < 0$
$\arg (-z)=\pi-\theta$
$\Rightarrow \arg (- z )-\arg ( z )=\pi-\theta-(-\theta)=\pi$