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  4. If area of triangle formed by the point (2 α, β),(α+β, 2 β+α) and (2 β, 2 α) is 8 square unit then area of triangle whose vertex are (α+β, α-β),(3 β-α, β+3 α) and (3 α-β, 3 β-α) is

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Q. If area of triangle formed by the point $(2 \alpha, \beta),(\alpha+\beta, 2 \beta+\alpha)$ and $(2 \beta, 2 \alpha)$ is 8 square unit then area of triangle whose vertex are $(\alpha+\beta, \alpha-\beta),(3 \beta-\alpha, \beta+3 \alpha)$ and $(3 \alpha-\beta, 3 \beta-\alpha)$ is

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Solution:

Area of $\triangle ABC =4(\triangle PQR )=4(\triangle PQR )=4 \times 8=32$ square unit