Thank you for reporting, we will resolve it shortly
Q.
If an unbiased die, marked with $-2,-1,0,1,2,3$ on its faces, is thrown five times, then the probability that the product of the outcomes is positive, is:
Either all outcomes are positive or any two are negative.
$ \text { Now, } p = P (\text { positive })=\frac{3}{6}=\frac{1}{2} $
$q = p (\text { negative })=\frac{2}{6}=\frac{1}{3}$
Required probability
$={ }^5 C_5\left(\frac{1}{2}\right)^5+{ }^5 C_2\left(\frac{1}{3}\right)^2\left(\frac{1}{2}\right)^3+{ }^5 C_4\left(\frac{1}{3}\right)^4\left(\frac{1}{2}\right)^1 $
$ =\frac{521}{2592}$