Q. If an organic compound contain $92.3\% \,C$ and $7.7\% \,H$, than number of $sp^3,sp^2$ and $sp$ hybridized carbon atoms in all possible structures of compound respectively are (molecular mass $= 52\,g/mol)$
Chemical Bonding and Molecular Structure
Solution:
Let amount of compound $=100 g$
No. of moles of $C =\frac{92.3}{12}=7.69=7.7$
No. of moles of $H =\frac{7.7}{1}=7.7$
Empirical formula $= CH$
Empirical formula mass $=12+1=13 \,g / mol$ Molecular mass $=52 \,g / mol$
$n=\frac{52}{13}=4$
$\therefore$ Molecular foumula = Empirical formula $\times 4= C _4 H _4$ Possible structures
