Thank you for reporting, we will resolve it shortly
Q.
If an emitter current is changed by $4 mA ,$ the collector current changes by $3.5 mA$. The value of $\beta$ will be
JEE MainJEE Main 2021Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
$I _{\varepsilon}= I _{ C }+ I _{ B }$
$\Rightarrow \Delta I _{\varepsilon}=\Delta I _{ C }+\Delta I _{ B }$
$4 mA =3.5 mA +\Delta I _{ B }$
$\Rightarrow \Delta I _{ B }=0.5 mA$
$\Rightarrow \beta=\frac{\Delta I _{ C }}{\Delta I _{ B }}$
$\beta=\frac{3.5}{0.5}$
$\Rightarrow \beta=7$