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Q. If an electron is revolving in its Bohr orbit having Bohr radius of $0.529 \,\mathring{A} $, then the radius of third orbit is

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Solution:

$r _{ n }=0.529 \times \frac{ n ^{2}}{ z } \,\,\,n =3$
$=0.529 \times 9=4.761 \,\mathring{A} $