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Question
Physics
If an electron drops from 4th orbit to 2nd orbit in an H-atom then
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Q. If an electron drops from 4th orbit to 2nd orbit in an H-atom then
Atoms
A
it gains 2.5 5 eV of potential energy
17%
B
it gains 2.55 eV of total energy
25%
C
it emits a 2.55 eV electron
28%
D
it emits a 2.55 eV photon
30%
Solution:
$E_n = - \frac{13.6 Z^2}{n^2} eV$
$\Delta \, E = E_4 - E_2$