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Q. If an electromagnetic wave of frequency $5 \,MHz$ travels from vacuum into dielectric medium of electrical permittivity $ε = 4$, then its (take $µ_r = 1$)

KEAMKEAM 2020

Solution:

Refractive index
$n=\sqrt{\mu_{r} \varepsilon_{r}}=\frac{\lambda_{\text {air }}}{\lambda_{\text {medium }}}$
Or $\lambda_{\text{med }}=\frac{\lambda_{\text {air }}}{\sqrt{\mu_{r} \varepsilon_{r}}}=\frac{\lambda}{\sqrt{4}}=\frac{\lambda}{2}$