Question

If an $E.coli$ with heavy $DNA$ is allowed to grow for $80$ minutes in a culture medium of $N14H4CI$, then what would be the proportion of heavy, light and hybrid densities $DNA$ molecule respectively?

• A. $\frac{1}{16}:\frac{2}{16}:\frac{14}{16}$
• B. $\frac{0}{16}:\frac{14}{16}:\frac{2}{16}$
• C. $\frac{1}{16}:\frac{14}{16}:\frac{2}{16}$
• D. $\frac{1}{8}:\frac{2}{8}:\frac{6}{8}$

Answer 1

Answer: (B)

Correct answer is (b) $\frac{0}{16}:\frac{14}{16}:\frac{2}{16}$