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  4. If an α-particle and a proton are accelerated from rest by a potential difference of 1 megavolt then the ratio of their kinetic energy will be

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Q. If an $\alpha$-particle and a proton are accelerated from rest by a potential difference of $1$ megavolt then the ratio of their kinetic energy will be

Electrostatic Potential and Capacitance

Solution:

$\Delta KE =q V$
$\frac{\Delta KE _{\alpha}}{\Delta KE _{p}}=\frac{q_{\alpha} V}{q_{p} V}=\frac{q_{\alpha}}{q_{p}}=2$