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Q. If an alpha particle and a proton are accelerated from rest by a potential difference of $1MeV$ , then the ratio of their kinetic energies will be

NTA AbhyasNTA Abhyas 2020Electrostatic Potential and Capacitance

Solution:

From conservation of mechanical energy
$\Delta KE=q\left(V_{i} - V_{f}\right)$
$\frac{K_{\alpha }}{K_{p}}=\frac{2 e \left(V\right)}{e \left(V\right)}$
$\frac{K_{\alpha }}{K_{p}}=\frac{2}{1}$