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Q.
If all meters are ideal and the reading of the voltmeter $3$ is $6V$ , then power supplied by the voltage source is
NTA AbhyasNTA Abhyas 2022
Solution:
Current through $20\Omega= \, \frac{6}{20}$
current through $10\Omega= \, \frac{6}{10}$
Total current supplied by voltage source
$=\frac{6}{10}+\frac{6}{20}$
$= 0.9 \text{ A}$
The voltage across voltmeter 4 = $0.9\times 30=27V$
Voltage of battery $= \, 6 \, + \, 27 \, = \, 33 \, volt$
Power supplied $=\frac{9}{10}\times \, 33$
$= \, 29.7or \, 30W$ ( Approx )
