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Q. If all integers satisfying the inequality $\frac{(x-1)^2(x-2)^3(x-4)^5(x-5)^5}{(x-5)^2} \geq 0$ are arranged in increasing order then the quadratic equation with the first and fifth integers in the list as roots is

Complex Numbers and Quadratic Equations

Solution:

$(x-2)^3(x-4)^5(x-5)^3 \geq 0 ; x=1, x \neq 5$
image
$x \in[2,4] \cup(5, \infty) \cup\{1\} \Rightarrow \text { integers }(1), 2,3,4,(6) \ldots \ldots$
Equation with roots 1,6
$ x ^2-7 x +6=0 $