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Physics
If absolute zero is -273. 15°C on Celsius temperature scale, then the absolute zero on the Fahrenheit scale is
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Q. If absolute zero is -273. 15$^{\circ}$C on Celsius temperature scale, then the absolute zero on the Fahrenheit scale is
Thermal Properties of Matter
A
-227.15$^{\circ}$F
14%
B
-453.15$^{\circ}$F
16%
C
-459.67$^{\circ}$ F
60%
D
-49l.67$^{\circ}$F
9%
Solution:
Celsius and Kelvin scale are related as
$ \, \, \, \, \, \, \, \, \, \, \frac{C}{5}=\frac{F-32}{9}$
or $ \, \, \, \, \, \, \, \, \frac{-273.15}{5}=\frac{F-32}{9}$
$\Rightarrow \, \, \, \, \, \, \, \, \, \, F=-459.67^{\circ}F $