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Q. If absolute zero is $ -273.15\text{ }{}^\circ C $ on Celsius temperature scale, then the absolute zero on the Fahrenheit scale is

VMMC MedicalVMMC Medical 2009

Solution:

Celsius and Kelvin scale are related as $ \frac{C}{5}=\frac{F-32}{9} $ or $ \frac{-273.15}{5}=\frac{F-32}{9} $ $ \Rightarrow $ $ F=-459.67\,{{\,}^{o}}F $