Question

If a semiconductor has an intrinsic carrier concentration of $ 1.41 \times 10^{16}\, /m^3 $ , when doped with $ 10^{21}\,/m^3 $ phosphorous atoms, then the concentration of holes/ $ m^3 $ at room temperature will be

• A. $ 2 \times 10^{21} $
• B. $ 2 \times 10^{11} $
• C. $ 1.41 \times 10^{10} $
• D. $ 1.41 \times 10^{16} $

Answer 1

Answer: (D)

Doping will increase the number of electrons only and not the holes. So, number of holes will be equal to number of intrinsic carrier concentration.
$=1.41 \times 10^{16} \,/ m ^{3}$