Thank you for reporting, we will resolve it shortly
Q.
If a Second’s pendulum is moved to a planet where acceleration due to gravity is $4$ times, the length of the
second’s pendulum on the planet should be made
Oscillations
Solution:
Time period of a pendulum
$T=2 \pi \sqrt{\frac{l}{g}} \text { or } T_{2} \sqrt{\frac{l}{g}}$
If $g$ becomes $4$ times. $l$ must also be increased by 4 times to keep $T$ constant.