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Q. If a Second’s pendulum is moved to a planet where acceleration due to gravity is $4$ times, the length of the second’s pendulum on the planet should be made

Oscillations

Solution:

Time period of a pendulum
$T=2 \pi \sqrt{\frac{l}{g}} \text { or } T_{2} \sqrt{\frac{l}{g}}$
If $g$ becomes $4$ times. $l$ must also be increased by 4 times to keep $T$ constant.