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  4. If a satellite of mass 400 kg revolves around the earth in an orbit with speed 200 m/s then its potential energy is

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Q. If a satellite of mass $400 \,kg$ revolves around the earth in an orbit with speed $200\, m/s$ then its potential energy is

Gravitation

Solution:

For a satellite,
$ P.E =-\frac{G M m}{r} $
$m =$ mass of satellite
$r =$ radius of orbit
$ K.E =\frac{1}{2} m v^{2}=\frac{G M m}{2 r}=-\frac{\text { P.E }}{2} $
$\Rightarrow P.E =-m v^{2} $
$=-400 \times 4 \times 10^{4} $
$=-16 \,MJ$