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Q. If a ray travelling in the direction $\frac{1}{2} (\hat{i} + \sqrt 3 \hat{j})$ is incident on a plane mirror. After reflection, the ray travels along the direction $\frac{1}{2} (\hat{i} - \sqrt 3 \hat{j})$ The angle of incidence is

UPSEEUPSEE 2015

Solution:

Angle between incident ray and reflected ray
$\cos \delta=\frac{(\hat{ i }+\sqrt{3} \hat{ j }) \cdot(\hat{ i }-3 \hat{ j })}{2 \cdot 2}$
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$\cos\, \delta=-\frac{1}{2} $
$ \Rightarrow \delta=120^{\circ}$
$ 180-\angle\, i=120 $
$ \Rightarrow \angle \,i=30^{\circ}$