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Q. If a planet has twice the mass of earth and three times the radius $(R)$ of earth, then the escape velocity of the planet is ($\upsilon_e$ = escape velocity of earth)

JIPMERJIPMER 2014Gravitation

Solution:

Escape velocity,$\upsilon_e = \sqrt{2gR}$
$ = \sqrt{\frac{2GM}{R^2}} R$ $\left( \because \:\: g = \frac{GM}{R^2} \right)$
$\therefore \:\: \upsilon_e \propto \sqrt{\frac{M}{R}}$ ...(i)
Given, $M_p = 2M$ and $R_p = 3R$
$\therefore \:\:\: (\upsilon_e)_p = \sqrt{\frac{2}{3}} \upsilon_e$ (Using (i))