Thank you for reporting, we will resolve it shortly
Q.
If a person can throw a stone to maximum height of $h$ metre vertically, then the maximum distance through which it can be thrown horizontally by the same person is
Using the equation of motion, we get
$h = \frac{u^2}{2g}$
thus, $u^2 = 2gh$
So the maximum horizontal distance would be given by
$R_{\text{max}} = \frac{u^2}{g} $( where $\theta = 45^{\circ})$
Hence $R_{\text{max}} = 2h$