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Q. If a neutral solution has $pK_w$ = 13.36 at 50$^\circ$C, then pH of the solution is

Equilibrium

Solution:

In a neutral solution
$\left[H^{+}\right]=\left[OH^{-}\right] \therefore pH=pOH $
$pK_{w}=pH+pOH $
$\therefore 2pH=13.36$
$\Rightarrow pH=\frac{13.36}{2}$
$=6.68$