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Q. If a metallic cylinder of radius $1 \mathrm{~m}$ and height $1.4 \mathrm{~m}$ is melted and recast into cube. The no. of cube if one cube has it edge $110 \mathrm{~cm}$

Mensuration

Solution:

Radius of cylinder $=7 \mathrm{~m}$
Height of the cylinder $=1.4 \mathrm{~cm}$
Volume of the cylinder $=\pi r^2 h$
Edge of the cube $=110 \mathrm{~cm}$
$=1.10 \mathrm{~m}$
$\text { No. of cube } =\frac{\text { Volume of the cylinder }}{\text { Volume of cube }} $
$ =\frac{\frac{22}{7} \times 7 \times 7 \times 1.4}{40 \times 1.10 \times 1.10}=\text { app }=162$