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Q. If a man goes $10 \,m$ toward north and $20\, m$ toward east, then his displacement is

Motion in a Straight Line

Solution:

image
Displacement $=AC=\sqrt{\left(AB\right)^{2}+\left(BC\right)^{2}}$
$=\sqrt{\left(10\,m\right)^{2}+\left(20\,m\right)^{2}}$
$=\sqrt{100+400} \approx 22.5\,m$