Question

If $ \text{a}=\text{lo}{{\text{g}}_{\text{24}}}\text{l2},\text{ b}=\text{lo}{{\text{g}}_{\text{36}}}\text{24} $ then $ \text{c }=\text{lo}{{\text{g}}_{\text{48}}}\text{36} $ is equal to

• A. $ e $
• B. $ -e $
• C. $ \text{2bc}-\text{1} $
• D. $ \text{2bc}+\text{1} $

Answer 1

Answer: (C)

When $ [F{{L}^{2}}{{L}^{-2}}] $ then $ [F{{L}^{-1}}{{T}^{2}}] $ $ [{{F}^{2}}L{{T}^{-2}}] $ $ 2{{O}_{3}}\to 3{{O}_{2}} $ $ {{O}_{3}}{{O}_{2}}+O......(fast) $ Now, $ O+{{O}_{3}}\xrightarrow{{}}2{{O}_{2}}\,\,\,......(Slow) $ $ r=k{{[{{O}_{3}}]}^{2}} $ $ r=k{{[{{O}_{3}}]}^{2}}{{[{{O}_{2}}]}^{-1}} $ $ r=k[{{O}_{3}}][{{O}_{2}}] $ $ Mg(s)+Z{{n}^{2+}}(aq)(0.1M)\to M{{g}^{2+}}(aq) $