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Q. If a graph is plotted between $T^2$ and $r^3$ for a planet, then its slope will be (where $M_S$ is the mass of the sun)

AMUAMU 2011Gravitation

Solution:

Time period of a revolution of a planet,
$T = \frac{2\pi r}{v} = \frac{2\pi r}{\sqrt{\frac{GM_{S}}{r}}} = \frac{2\pi r^{3/2}}{\sqrt{GM_{S}}}$
where $M_{S}$ is the mass of the sun
Squaring both sides, we get
$T^{2} = \frac{4\pi^{2}r^{2}}{GM_{S}}$
The graph between $T^{2}$ and $r^{3}$ is a straight line whose slope is $\frac{4\pi^{2}}{GM_{S}}$