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Q. If a bar magnet of magnetic moment M is kept in a uniform magnetic field B, its time period of oscillation is T. In the same magnetic field, the time period of another magnet of same dimension and same mass but of moment M/4 is,

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Solution:

$T=2\pi\sqrt{\frac{1}{MB}}, T'=2\pi\sqrt{\frac{1}{\frac{M}{4}B}}=2T$