Thank you for reporting, we will resolve it shortly
Q.
If $a, b\,\in\left(1, 2, 3\right)$ and the equation $ax^2 + bx + 1 = 0$ has real roots, then
WBJEEWBJEE 2017Complex Numbers and Quadratic Equations
Solution:
We have,
$a x^{2}+b x+1=0$
For real roots, $D \geq 0$
$\therefore {b}^{2}-4 a \geq 0 $
$\Rightarrow b^{2} \geq 4 a $
$\therefore (a, b)=(1,2),(1,3),(2,3)$
$\therefore $ Number of ordered pairs $(a, b)=3$
and $a$ is always less than $b$.