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Q.
If $A B C D E F$ is a regular hexagon with $A B = a$ and $B C = b$, then $C E$ equals
Bihar CECEBihar CECE 2012
Solution:
In $\triangle A B C, A B+B C=A C$
$\Rightarrow A C = a + b$
$A D$ is parallel to $B C$ and $A D=2 B C$
$\therefore A D =2 b$
In $\triangle A C D, A C+C D=A D$
$\Rightarrow C D=2 b-(a+ b)=b-a$
Now, $C E = C D + D E = b -2 a$
