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Mathematics
If a, b, c are positive numbers in A.P., such that their product is 64, then the minimum value of b is equal to
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Q. If $a, b, c$ are positive numbers in $A.P$., such that their product is $64$, then the minimum value of $b$ is equal to
Sequences and Series
A
$2$
14%
B
$4$
59%
C
$1$
20%
D
$5$
8%
Solution:
Given $a+c = 2b $
Also $\frac{a+b+c}{3} \ge \sqrt[3]{abc} $
$= \sqrt[3]{64} = 4 $
$ \Rightarrow \frac{3b}{3} \ge 4$
$ \Rightarrow b\ge 4$
$ \Rightarrow $ minimum value of $b = 4 $