1. Tardigrade
  2. Question
  3. Mathematics
  4. If a, b, c>0 and x, y, z ∈ R, then the determinant |(ax+a-x)2 (ax-a-x)2 1 (by+b-y)2 (by-b-y)2 1 (cz+c-z)2 (cz-c-z)2 1| is equal to -

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Q. If $a, b, c>0$ and $x, y, z \in R$, then the determinant $\begin{vmatrix}\left(a^x+a^{-x}\right)^2 & \left(a^x-a^{-x}\right)^2 & 1 \\ \left(b^y+b^{-y}\right)^2 & \left(b^y-b^{-y}\right)^2 & 1 \\ \left(c^z+c^{-z}\right)^2 & \left(c^z-c^{-z}\right)^2 & 1\end{vmatrix}$ is equal to -

Determinants

Solution:

$C_1 \rightarrow C_1-C_2$