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Q.
If $A$ and $B$ are two mutually exclusive events, then :
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Solution:
$\because A$ and $B$ are two mutually exclusive events
$\therefore A \cap B=\phi \Rightarrow A \subseteq \bar{B}$ and $B \subseteq \wedge$
$\Rightarrow P(\Lambda) \leq P(\bar{B})$ and $P(B) \leq P(\bar{\Lambda})$
Note : Two events $A$ and $B$ are said to be mutually exclusive events if $A \cap B=\phi$.