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Q. If $A$ and $B$ are mutually exclusive events such that $p(A)=0.5$ and $p(A \cup B)=0.75$, then $P(B)$ is equal to

KEAMKEAM 2020

Solution:

$P(A \cup B)=P(A)+P(B)$
$P(B)=(A \cup B)-P(A)$
$=0.75-0.5$
$=0.25$